Integrand size = 16, antiderivative size = 112 \[ \int x^{5/2} \sqrt {2-b x} \, dx=-\frac {5 \sqrt {x} \sqrt {2-b x}}{8 b^3}-\frac {5 x^{3/2} \sqrt {2-b x}}{24 b^2}-\frac {x^{5/2} \sqrt {2-b x}}{12 b}+\frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {5 \arcsin \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )}{4 b^{7/2}} \]
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Time = 0.02 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {52, 56, 222} \[ \int x^{5/2} \sqrt {2-b x} \, dx=\frac {5 \arcsin \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )}{4 b^{7/2}}-\frac {5 \sqrt {x} \sqrt {2-b x}}{8 b^3}-\frac {5 x^{3/2} \sqrt {2-b x}}{24 b^2}+\frac {1}{4} x^{7/2} \sqrt {2-b x}-\frac {x^{5/2} \sqrt {2-b x}}{12 b} \]
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Rule 52
Rule 56
Rule 222
Rubi steps \begin{align*} \text {integral}& = \frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {1}{4} \int \frac {x^{5/2}}{\sqrt {2-b x}} \, dx \\ & = -\frac {x^{5/2} \sqrt {2-b x}}{12 b}+\frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {5 \int \frac {x^{3/2}}{\sqrt {2-b x}} \, dx}{12 b} \\ & = -\frac {5 x^{3/2} \sqrt {2-b x}}{24 b^2}-\frac {x^{5/2} \sqrt {2-b x}}{12 b}+\frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {5 \int \frac {\sqrt {x}}{\sqrt {2-b x}} \, dx}{8 b^2} \\ & = -\frac {5 \sqrt {x} \sqrt {2-b x}}{8 b^3}-\frac {5 x^{3/2} \sqrt {2-b x}}{24 b^2}-\frac {x^{5/2} \sqrt {2-b x}}{12 b}+\frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {5 \int \frac {1}{\sqrt {x} \sqrt {2-b x}} \, dx}{8 b^3} \\ & = -\frac {5 \sqrt {x} \sqrt {2-b x}}{8 b^3}-\frac {5 x^{3/2} \sqrt {2-b x}}{24 b^2}-\frac {x^{5/2} \sqrt {2-b x}}{12 b}+\frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {5 \text {Subst}\left (\int \frac {1}{\sqrt {2-b x^2}} \, dx,x,\sqrt {x}\right )}{4 b^3} \\ & = -\frac {5 \sqrt {x} \sqrt {2-b x}}{8 b^3}-\frac {5 x^{3/2} \sqrt {2-b x}}{24 b^2}-\frac {x^{5/2} \sqrt {2-b x}}{12 b}+\frac {1}{4} x^{7/2} \sqrt {2-b x}+\frac {5 \sin ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )}{4 b^{7/2}} \\ \end{align*}
Time = 0.29 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.77 \[ \int x^{5/2} \sqrt {2-b x} \, dx=\frac {\sqrt {x} \sqrt {2-b x} \left (-15-5 b x-2 b^2 x^2+6 b^3 x^3\right )}{24 b^3}-\frac {5 \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}-\sqrt {2-b x}}\right )}{2 b^{7/2}} \]
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Time = 0.11 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.79
method | result | size |
meijerg | \(\frac {\frac {\sqrt {\pi }\, \sqrt {x}\, \sqrt {2}\, \left (-b \right )^{\frac {7}{2}} \left (-42 b^{3} x^{3}+14 b^{2} x^{2}+35 b x +105\right ) \sqrt {-\frac {b x}{2}+1}}{168 b^{3}}-\frac {5 \sqrt {\pi }\, \left (-b \right )^{\frac {7}{2}} \arcsin \left (\frac {\sqrt {b}\, \sqrt {x}\, \sqrt {2}}{2}\right )}{4 b^{\frac {7}{2}}}}{\left (-b \right )^{\frac {5}{2}} \sqrt {\pi }\, b}\) | \(89\) |
risch | \(-\frac {\left (6 b^{3} x^{3}-2 b^{2} x^{2}-5 b x -15\right ) \sqrt {x}\, \left (b x -2\right ) \sqrt {\left (-b x +2\right ) x}}{24 b^{3} \sqrt {-x \left (b x -2\right )}\, \sqrt {-b x +2}}+\frac {5 \arctan \left (\frac {\sqrt {b}\, \left (x -\frac {1}{b}\right )}{\sqrt {-b \,x^{2}+2 x}}\right ) \sqrt {\left (-b x +2\right ) x}}{8 b^{\frac {7}{2}} \sqrt {x}\, \sqrt {-b x +2}}\) | \(115\) |
default | \(-\frac {x^{\frac {5}{2}} \left (-b x +2\right )^{\frac {3}{2}}}{4 b}+\frac {-\frac {5 x^{\frac {3}{2}} \left (-b x +2\right )^{\frac {3}{2}}}{12 b}+\frac {5 \left (-\frac {\sqrt {x}\, \left (-b x +2\right )^{\frac {3}{2}}}{2 b}+\frac {\sqrt {x}\, \sqrt {-b x +2}+\frac {\sqrt {\left (-b x +2\right ) x}\, \arctan \left (\frac {\sqrt {b}\, \left (x -\frac {1}{b}\right )}{\sqrt {-b \,x^{2}+2 x}}\right )}{\sqrt {-b x +2}\, \sqrt {x}\, \sqrt {b}}}{2 b}\right )}{4 b}}{b}\) | \(128\) |
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Time = 0.23 (sec) , antiderivative size = 141, normalized size of antiderivative = 1.26 \[ \int x^{5/2} \sqrt {2-b x} \, dx=\left [\frac {{\left (6 \, b^{4} x^{3} - 2 \, b^{3} x^{2} - 5 \, b^{2} x - 15 \, b\right )} \sqrt {-b x + 2} \sqrt {x} - 15 \, \sqrt {-b} \log \left (-b x + \sqrt {-b x + 2} \sqrt {-b} \sqrt {x} + 1\right )}{24 \, b^{4}}, \frac {{\left (6 \, b^{4} x^{3} - 2 \, b^{3} x^{2} - 5 \, b^{2} x - 15 \, b\right )} \sqrt {-b x + 2} \sqrt {x} - 30 \, \sqrt {b} \arctan \left (\frac {\sqrt {-b x + 2}}{\sqrt {b} \sqrt {x}}\right )}{24 \, b^{4}}\right ] \]
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Result contains complex when optimal does not.
Time = 26.49 (sec) , antiderivative size = 250, normalized size of antiderivative = 2.23 \[ \int x^{5/2} \sqrt {2-b x} \, dx=\begin {cases} \frac {i b x^{\frac {9}{2}}}{4 \sqrt {b x - 2}} - \frac {7 i x^{\frac {7}{2}}}{12 \sqrt {b x - 2}} - \frac {i x^{\frac {5}{2}}}{24 b \sqrt {b x - 2}} - \frac {5 i x^{\frac {3}{2}}}{24 b^{2} \sqrt {b x - 2}} + \frac {5 i \sqrt {x}}{4 b^{3} \sqrt {b x - 2}} - \frac {5 i \operatorname {acosh}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )}}{4 b^{\frac {7}{2}}} & \text {for}\: \left |{b x}\right | > 2 \\- \frac {b x^{\frac {9}{2}}}{4 \sqrt {- b x + 2}} + \frac {7 x^{\frac {7}{2}}}{12 \sqrt {- b x + 2}} + \frac {x^{\frac {5}{2}}}{24 b \sqrt {- b x + 2}} + \frac {5 x^{\frac {3}{2}}}{24 b^{2} \sqrt {- b x + 2}} - \frac {5 \sqrt {x}}{4 b^{3} \sqrt {- b x + 2}} + \frac {5 \operatorname {asin}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )}}{4 b^{\frac {7}{2}}} & \text {otherwise} \end {cases} \]
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Time = 0.29 (sec) , antiderivative size = 147, normalized size of antiderivative = 1.31 \[ \int x^{5/2} \sqrt {2-b x} \, dx=\frac {\frac {15 \, \sqrt {-b x + 2} b^{3}}{\sqrt {x}} - \frac {73 \, {\left (-b x + 2\right )}^{\frac {3}{2}} b^{2}}{x^{\frac {3}{2}}} - \frac {55 \, {\left (-b x + 2\right )}^{\frac {5}{2}} b}{x^{\frac {5}{2}}} - \frac {15 \, {\left (-b x + 2\right )}^{\frac {7}{2}}}{x^{\frac {7}{2}}}}{12 \, {\left (b^{7} - \frac {4 \, {\left (b x - 2\right )} b^{6}}{x} + \frac {6 \, {\left (b x - 2\right )}^{2} b^{5}}{x^{2}} - \frac {4 \, {\left (b x - 2\right )}^{3} b^{4}}{x^{3}} + \frac {{\left (b x - 2\right )}^{4} b^{3}}{x^{4}}\right )}} - \frac {5 \, \arctan \left (\frac {\sqrt {-b x + 2}}{\sqrt {b} \sqrt {x}}\right )}{4 \, b^{\frac {7}{2}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 216 vs. \(2 (79) = 158\).
Time = 12.08 (sec) , antiderivative size = 216, normalized size of antiderivative = 1.93 \[ \int x^{5/2} \sqrt {2-b x} \, dx=\frac {\frac {{\left ({\left ({\left (b x - 2\right )} {\left (2 \, {\left (b x - 2\right )} {\left (\frac {3 \, {\left (b x - 2\right )}}{b^{3}} + \frac {25}{b^{3}}\right )} + \frac {163}{b^{3}}\right )} + \frac {279}{b^{3}}\right )} \sqrt {{\left (b x - 2\right )} b + 2 \, b} \sqrt {-b x + 2} - \frac {210 \, \log \left ({\left | -\sqrt {-b x + 2} \sqrt {-b} + \sqrt {{\left (b x - 2\right )} b + 2 \, b} \right |}\right )}{\sqrt {-b} b^{2}}\right )} {\left | b \right |}}{b} - \frac {8 \, {\left (\sqrt {{\left (b x - 2\right )} b + 2 \, b} \sqrt {-b x + 2} {\left ({\left (b x - 2\right )} {\left (\frac {2 \, {\left (b x - 2\right )}}{b^{2}} + \frac {13}{b^{2}}\right )} + \frac {33}{b^{2}}\right )} - \frac {30 \, \log \left ({\left | -\sqrt {-b x + 2} \sqrt {-b} + \sqrt {{\left (b x - 2\right )} b + 2 \, b} \right |}\right )}{\sqrt {-b} b}\right )} {\left | b \right |}}{b^{2}}}{24 \, b} \]
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Timed out. \[ \int x^{5/2} \sqrt {2-b x} \, dx=\int x^{5/2}\,\sqrt {2-b\,x} \,d x \]
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